May 21Medium
Find the length of the longest common prefix
- Array
- Hash Table
- String
- Trie
Problem
You are given two arrays with positive integers arr1 and arr2.
A prefix of a positive integer is an integer formed by one or more of its digits, starting from its leftmost digit. For example, 123 is a prefix of the integer 12345, while 234 is not.
A common prefix of two integers a and b is an integer c, such that c is a prefix of both a and b. For example, 5655359 and 56554 have common prefixes 565 and 5655 while 1223 and 43456 do not have a common prefix.
You need to find the length of the longest common prefix between all pairs of integers (x, y) such that x belongs to arr1 and y belongs to arr2.
Return the length of the longest common prefix among all pairs. If no common prefix exists among them, return 0.
Solution
class Solution:
def longestCommonPrefix(self, arr1: List[int], arr2: List[int]) -> int:
prefixes = set()
for el in arr2:
str_el = str(el)
for i in range(len(str_el)):
prefixes.add(str_el[:i+1])
res = 0
for el in arr1:
str_el = str(el)
i = 1
while i <= len(str_el) and str_el[:i] in prefixes:
res = max(res, i)
i += 1
return res